Optimal. Leaf size=396 \[ \frac {3 \sqrt {2} A \tan (c+d x) F_1\left (\frac {1}{6};\frac {1}{2},1;\frac {7}{6};\frac {1}{2} (\sec (c+d x)+1),\sec (c+d x)+1\right )}{a d \sqrt {1-\sec (c+d x)} \sqrt [3]{a \sec (c+d x)+a}}-\frac {3 (A+C) \tan (c+d x)}{5 d (a \sec (c+d x)+a)^{4/3}}+\frac {3^{3/4} (A-4 C) \tan (c+d x) \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right ) \sqrt {\frac {(\sec (c+d x)+1)^{2/3}+\sqrt [3]{2} \sqrt [3]{\sec (c+d x)+1}+2^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} F\left (\cos ^{-1}\left (\frac {\sqrt [3]{2}-\left (1-\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}}{\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{5 \sqrt [3]{2} a d (1-\sec (c+d x)) \sqrt {-\frac {\sqrt [3]{\sec (c+d x)+1} \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} \sqrt [3]{a \sec (c+d x)+a}} \]
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Rubi [A] time = 0.46, antiderivative size = 396, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 9, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {4053, 3924, 3779, 3778, 136, 3828, 3827, 63, 225} \[ \frac {3 \sqrt {2} A \tan (c+d x) F_1\left (\frac {1}{6};\frac {1}{2},1;\frac {7}{6};\frac {1}{2} (\sec (c+d x)+1),\sec (c+d x)+1\right )}{a d \sqrt {1-\sec (c+d x)} \sqrt [3]{a \sec (c+d x)+a}}-\frac {3 (A+C) \tan (c+d x)}{5 d (a \sec (c+d x)+a)^{4/3}}+\frac {3^{3/4} (A-4 C) \tan (c+d x) \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right ) \sqrt {\frac {(\sec (c+d x)+1)^{2/3}+\sqrt [3]{2} \sqrt [3]{\sec (c+d x)+1}+2^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} F\left (\cos ^{-1}\left (\frac {\sqrt [3]{2}-\left (1-\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}}{\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{5 \sqrt [3]{2} a d (1-\sec (c+d x)) \sqrt {-\frac {\sqrt [3]{\sec (c+d x)+1} \left (\sqrt [3]{2}-\sqrt [3]{\sec (c+d x)+1}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{\sec (c+d x)+1}\right )^2}} \sqrt [3]{a \sec (c+d x)+a}} \]
Antiderivative was successfully verified.
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Rule 63
Rule 136
Rule 225
Rule 3778
Rule 3779
Rule 3827
Rule 3828
Rule 3924
Rule 4053
Rubi steps
\begin {align*} \int \frac {A+C \sec ^2(c+d x)}{(a+a \sec (c+d x))^{4/3}} \, dx &=-\frac {3 (A+C) \tan (c+d x)}{5 d (a+a \sec (c+d x))^{4/3}}-\frac {3 \int \frac {-\frac {5 a A}{3}+\frac {1}{3} a (A-4 C) \sec (c+d x)}{\sqrt [3]{a+a \sec (c+d x)}} \, dx}{5 a^2}\\ &=-\frac {3 (A+C) \tan (c+d x)}{5 d (a+a \sec (c+d x))^{4/3}}+\frac {A \int \frac {1}{\sqrt [3]{a+a \sec (c+d x)}} \, dx}{a}-\frac {(A-4 C) \int \frac {\sec (c+d x)}{\sqrt [3]{a+a \sec (c+d x)}} \, dx}{5 a}\\ &=-\frac {3 (A+C) \tan (c+d x)}{5 d (a+a \sec (c+d x))^{4/3}}+\frac {\left (A \sqrt [3]{1+\sec (c+d x)}\right ) \int \frac {1}{\sqrt [3]{1+\sec (c+d x)}} \, dx}{a \sqrt [3]{a+a \sec (c+d x)}}-\frac {\left ((A-4 C) \sqrt [3]{1+\sec (c+d x)}\right ) \int \frac {\sec (c+d x)}{\sqrt [3]{1+\sec (c+d x)}} \, dx}{5 a \sqrt [3]{a+a \sec (c+d x)}}\\ &=-\frac {3 (A+C) \tan (c+d x)}{5 d (a+a \sec (c+d x))^{4/3}}-\frac {(A \tan (c+d x)) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x} x (1+x)^{5/6}} \, dx,x,\sec (c+d x)\right )}{a d \sqrt {1-\sec (c+d x)} \sqrt [6]{1+\sec (c+d x)} \sqrt [3]{a+a \sec (c+d x)}}+\frac {((A-4 C) \tan (c+d x)) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x} (1+x)^{5/6}} \, dx,x,\sec (c+d x)\right )}{5 a d \sqrt {1-\sec (c+d x)} \sqrt [6]{1+\sec (c+d x)} \sqrt [3]{a+a \sec (c+d x)}}\\ &=-\frac {3 (A+C) \tan (c+d x)}{5 d (a+a \sec (c+d x))^{4/3}}+\frac {3 \sqrt {2} A F_1\left (\frac {1}{6};\frac {1}{2},1;\frac {7}{6};\frac {1}{2} (1+\sec (c+d x)),1+\sec (c+d x)\right ) \tan (c+d x)}{a d \sqrt {1-\sec (c+d x)} \sqrt [3]{a+a \sec (c+d x)}}+\frac {(6 (A-4 C) \tan (c+d x)) \operatorname {Subst}\left (\int \frac {1}{\sqrt {2-x^6}} \, dx,x,\sqrt [6]{1+\sec (c+d x)}\right )}{5 a d \sqrt {1-\sec (c+d x)} \sqrt [6]{1+\sec (c+d x)} \sqrt [3]{a+a \sec (c+d x)}}\\ &=-\frac {3 (A+C) \tan (c+d x)}{5 d (a+a \sec (c+d x))^{4/3}}+\frac {3 \sqrt {2} A F_1\left (\frac {1}{6};\frac {1}{2},1;\frac {7}{6};\frac {1}{2} (1+\sec (c+d x)),1+\sec (c+d x)\right ) \tan (c+d x)}{a d \sqrt {1-\sec (c+d x)} \sqrt [3]{a+a \sec (c+d x)}}+\frac {3^{3/4} (A-4 C) F\left (\cos ^{-1}\left (\frac {\sqrt [3]{2}-\left (1-\sqrt {3}\right ) \sqrt [3]{1+\sec (c+d x)}}{\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{1+\sec (c+d x)}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right ) \left (\sqrt [3]{2}-\sqrt [3]{1+\sec (c+d x)}\right ) \sqrt {\frac {2^{2/3}+\sqrt [3]{2} \sqrt [3]{1+\sec (c+d x)}+(1+\sec (c+d x))^{2/3}}{\left (\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{1+\sec (c+d x)}\right )^2}} \tan (c+d x)}{5 \sqrt [3]{2} a d (1-\sec (c+d x)) \sqrt [3]{a+a \sec (c+d x)} \sqrt {-\frac {\sqrt [3]{1+\sec (c+d x)} \left (\sqrt [3]{2}-\sqrt [3]{1+\sec (c+d x)}\right )}{\left (\sqrt [3]{2}-\left (1+\sqrt {3}\right ) \sqrt [3]{1+\sec (c+d x)}\right )^2}}}\\ \end {align*}
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Mathematica [F] time = 3.09, size = 0, normalized size = 0.00 \[ \int \frac {A+C \sec ^2(c+d x)}{(a+a \sec (c+d x))^{4/3}} \, dx \]
Verification is Not applicable to the result.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {C \sec \left (d x + c\right )^{2} + A}{{\left (a \sec \left (d x + c\right ) + a\right )}^{\frac {4}{3}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.46, size = 0, normalized size = 0.00 \[ \int \frac {A +C \left (\sec ^{2}\left (d x +c \right )\right )}{\left (a +a \sec \left (d x +c \right )\right )^{\frac {4}{3}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {C \sec \left (d x + c\right )^{2} + A}{{\left (a \sec \left (d x + c\right ) + a\right )}^{\frac {4}{3}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {A+\frac {C}{{\cos \left (c+d\,x\right )}^2}}{{\left (a+\frac {a}{\cos \left (c+d\,x\right )}\right )}^{4/3}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {A + C \sec ^{2}{\left (c + d x \right )}}{\left (a \left (\sec {\left (c + d x \right )} + 1\right )\right )^{\frac {4}{3}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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